Question

Who is the centre of the semicircle of a semicircular arc acb is a straight line find the shaded region?

Answer 1

Answer:

Step-by-step explanation:

In right triangle AED AD2=AE2+DE2

= =92+122 = 81+144 = 225

Therefore,AD2=225

⇒AD=15

Area of the shaded region = Area of rectangle – Area of triangle AED + Area of semicircle

=AB×BC–12×AE×DE+12π(BC2)2

=20×15–12×9×12+12×3.14(152)2

=300–54+88.31

= 334.31 cm2

Hence, the area of shaded region is 334.31 cm2