Math, asked by rekha693822, 23 days ago

who will answer first with neat explanation I will mark you as brainliest​

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Answers

Answered by anumulamourya26
1

Answer:

x = 55° y & z = 125°

Step-by-step explanation:

x is opposite angle of the give so it is 55°

y and z are opposite so are equal. y = z

y and 55° are supplementary angles as they lie on the same line.

y + 55° = 180°

y = 180 - 55° = 125°

Hence,

x = 55°

y = 125°

z = 125°

IF THIS WAS HELPFUL TO YOU PLS MARK ME AS BRAINLIEST

Answered by MasterDhruva
3

How to do :-

Here, we are given with two lines that intersect each other. They are forming a pair of vertically opposite angles. We know that the vertically opposite angles are always equal. We also know that a straight line always adds up to 180°. So, if we know one angle we can find the second angle that is forming a straight line. Here, we should use two concepts those are vertically opposite angles and the straight line always forms an angle of 180°. So, let's solve!!

\:

Solution :-

Value of 'x' :-

We know that the vertically opposite angles are always same. So,

{\tt \leadsto \pink{\underline{\boxed{\tt \angle{x} = {55}^{\circ}}}}}

\:

Value of 'y' :-

We know that a straight line always measures 180°. So,

{\tt \leadsto {55}^{\circ} + \angle{y} = {180}^{\circ}}

Remove the degree symbol which makes easier to solve.

{\tt \leadsto 55 + \angle{y} = 180}

Shift the number 55 from LHS to RHS, changing it's sign.

{\tt \leadsto \angle{y} = 180 - 55}

Subtract the values to get the value of y.

{\tt \leadsto \pink{\underline{\boxed{\tt \angle{y} = {125}^{\circ}}}}}

\:

Value of z :-

We know that a straight line always measures 180°. So,

{\tt \leadsto {55}^{\circ} + \angle{z} = {180}^{\circ}}

Remove the degree symbol which makes easier to solve.

{\tt \leadsto 55 + \angle{z} = 180}

Shift the number 55 from LHS to RHS, changing it's sign.

{\tt \leadsto \angle{z} = 180 - 55}

Subtract the values to get the value of z.

{\tt \leadsto \pink{\underline{\boxed{\tt \angle{z} = {125}^{\circ}}}}}

\:

Hence solved !!

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