Question

Who will solve this answer first I will follow him and mark as brainliest
1. There are two parks A and B as shown
below.
30 m
Park A
30 m
Park B
75 m
75 m
​

Answer 1

Answer :

Park B has greater area than park A by 706.5 m²

Step-by-step explanation :

To know which park has greater area, we have to find out separately the areas of parks A and B.

Area of park A :

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= Area of rectangle of dimension 75 m × 30 m - Area of semicircle of diameter 30 m

$\sf =(75 \ m \times 30 \ m) -\pi \dfrac{d^2}{8} \\\\ \sf =(75 \times 30 ) -\bigg(3.14\times \dfrac{30^2}{8} \bigg)\\\\ \sf =(2250 ) -\bigg(3.14 \times \dfrac{900}{8} \bigg ) \\\\ = 2250-\bigg(3.14 \times 112.5 \bigg) \\\\ = 2250-353.25 \\\\ =1896.75 \ m^2$

Area of park B :

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= Area of rectangle of dimension 75 m × 30 m + Area of semicircle of diameter 30 m

$\sf =(75 \ m \times 30 \ m) +\pi \dfrac{d^2}{8} \\\\ \sf =(75 \times 30 ) +\bigg(3.14\times \dfrac{30^2}{8} \bigg)\\\\ \sf =(2250 ) +\bigg(3.14 \times \dfrac{900}{8} \bigg ) \\\\ = 2250+\bigg(3.14 \times 112.5 \bigg) \\\\ = 2250+353.25 \\\\ =2603.25 \ m^2$

2603.25 m² > 1896.75 m²

2603.25 m² - 1896.75 m² = 706.5 m²

Therefore, Park B has greater area than park A by 706.5 m²

--------------------------------

[Area of semicircle = πr²/2 = πd²/8 ]

Answer 2

Answer:

Step-by-step explanation:

$\huge\sf\underline\green{answer}$

1)area of park A:

$formula of area of park A= area of rectangle-area of semicircle$

given,

length of rectangle = 75m

breadth of rectangle = 30m

radius of semicircle = diameter of semicircle/2 = 30m/2 = 15m

area of rectangle = l*b = 75m*30m = 2250m^2

area of semicircle= πr^2/2 = 3.14*(15^2)/2= 3.14*225/2 = 706.85/2= 353.42m^2

area of park A= 2250m^2-353.42m^2=1896.58m^2

2) area of park B:

$formula of area of park B= area of rectangle+area of semicircle$

length of rectangle = 75m

breadth of rectangle = 30m

radius of semicircle = diameter of semicircle/2 = 30m/2 = 15m

area of rectangle = l*b = 75m*30m = 2250m^2

area of semicircle= πr^2/2 = 3.14*(15^2)/2= 3.14*225/2 = 706.85/2= 353.42m^2

area of park B= 2250m^2+353.42m^2=2603.42m^2

:. area of park B is grater than area of park A .

by:

2603.42m^2-1896.58m^2=706.84