Math, asked by anucshree, 9 months ago

whoever does this will receive brainliest​

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Answered by hazel908
1
Let the cost price of the table be Rs x and the cost price of the chair be Rs y.
The selling price of the table, when it is sold at a profit of 10% = Rs x + 10x/100 = 110x / 100

The selling price of the chair when it is sold at a profit of 25% = Rs y + 25y/100 = 125y / 100

So, 110x / 100 + 125y / 100 = 1050 ... (1)

When the table is sold at a profit of 25%, its selling price = Rs (x + 25x/100) = Rs 125x / 100

When the chair is sold at a profit of 10%, its selling price = Rs (y + 10y/100) = Rs 110y / 100

So, 125x / 100 + 110y / 100 = 1065 ... (2)

Solve (1) and (2), to get x = 500 and y = 400

Hence. the cost price of the table is Rs 500 and the cost price of the chair is Rs 400.
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