Question

Whole cube of (a+b+c)3​

Answer 1

$(a + b + c) {}^{3} = (a + b + c) \times (a + b + c) \times (a + b + c) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = ( (a + b + c) (a + b + c) (a + b + c)) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (a {}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac) (a + b + c) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {a}^{3} + b {}^{3} + {c}^{ 3} + 3 {a}^{2} b + 3 {b}^{2} c + 3ac {}^{2}$

Answer 2

a^3+b^3+c^3+3a^2 b+3b^2 c+3ac^2 .

Hope it will help you