Whole prove formula to prove that a quadrilateral is a parallelogram if its one paur of opposite sides are equal and parallel
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Answer:
b-q plus a
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AC is a transversal and also AB║CD, therefore
∠BAC=∠DCA(Alternate angles)
In ΔADC and ΔCBA, we have
AB=CD(Given)
∠BAC=∠DCA(Alternate angles)
AC=CA(Common)
ΔADC≅ΔCBA by the SAS rule.
Hence, by CPCT, DA=BC
Thus, Both the pair of opposite sides are equal in the quadrilateral ABCD, therefore ABCD is a parallelogram.
Hence proved.
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