Question

The reseelteent of two forces p and 15N is 20N inclined at 60 to the 15N force. Find the magnitade and direction P.​

Answer 1

Answer:

Solution

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Correct option is C)

The resultant of two vectors:

P

and

Q

is given by

R=

P

2

+Q

2

+2PQcosθ

where, P and Q are magnitudes of two vectors and θ is the angle between two vectors.

Here θ=? P=8N Q=15N R=17N

Therefore,

17=

8

2

+15

2

+2×8×15cosθ

289=64+225+240cosθ

289=289+240cosθ

289−289=240cosθ

cosθ=0

cosθ=cos90

θ=90

0