Question

Whole root of 999 * 1000 * 1001 * 1002 + 1

Answer 1

Given: The term √( 999 * 1000 * 1001 * 1002 + 1 )

To find: The value of the given term?

Solution:

• Now we have given : √( 999 * 1000 * 1001 * 1002 + 1 )

• Let n = 999, then:

                  √( n x (n+1) x (n+2) x (n+3) + 1 )

                  √ ( (n² + 3n) x (n² + 3n + 2) + 1 )

• Now let n² + 3n = y, then we get:

                  √ ( y x (y + 2) + 1 )

                  √ ( y² x 2y + 1 )

                  √ ( y + 1 )²

                  y + 1

• Now again re substituting the values, we get:

                  n² + 3n + 1

• Putting n = 999, we get:

                  999² + 3(999) + 1

                  998001 + 2997 + 1

                  1000999

Answer:

              So the square root of the given term is: 1000999

Answer 2

Step-by-step explanation:

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