Question

whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime number so that the resultant number is perfect square of 32

Answer 1

Let y is the required number.

a/c to question,

y² + greatest three digit prime number + smallest two digit prime number = 32²

we know, greatest three digit prime number = 997

smallest two digit prime number = 11

now, y² + 997 + 11 = 32²

or, y² + 1008 = 1024

or, y² = 1024 - 1008

or, y² = 16

or, y = 4

hence, required number number is one digit even number e.g., y = 4

Answer 2

Answer:

±4

Step-by-step explanation:

Whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime number so that the resultant number is perfect square of 32

Let say x is the number whose perfect square to be added

greatest three digit prime number = 997   ( as 999 & 998 are not prime numbers)

Smallest two digit prime number = 11  ( as 10 is not prime number)

So

x² + 997 + 11 = 32²

=> x² + 1008 = 1024

=> x² = 1024 - 1008

=> x² = 16

=> x = ±4

4 or -4  is the answer