whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime numberso that the resultant number is perfect square of 32
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4
Answer:
± 4
Step-by-step explanation:
Given whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime number so that the resultant number is perfect square of 32
Let p be the required number.
We know that greatest three digit prime number is 997
smallest two digit prime number is 11
Now according to question we have
p^2 + 997 + 11 = 32^2
p^2 + 1008 = 1024
p^2 = 1024 - 1008
p^2 = 16
p = ± 4
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