Math, asked by geeta1159, 1 year ago

whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime numberso that the resultant number is perfect square of 32​

Answers

Answered by knjroopa
4

Answer:

± 4

Step-by-step explanation:

Given whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime number so that the resultant number is perfect square of 32​

Let p be the required number.

We know that greatest three digit prime number is 997

                   smallest two digit prime number is 11

Now according to question we have

            p^2 + 997 + 11 = 32^2

          p^2 + 1008 = 1024

          p^2 = 1024 - 1008

          p^2 = 16

         p = ± 4

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