Question

) Whose value may be zero for a moving particle -(a) Displacement(b) Distance(c) Speed(d) None of these​

Answer 1

Answer

( a ) Displacement

Explanation

During some time interval for a moving particle distance can't be zero .

So , Speed also can't be zero .

But displacement may be zero .

Reason :

Displacement is defined as shortest distance b/w final and initial positions .

So , final position may coincide with initial position . Hence , Displacement may be zero .

More Info

• Distance is a scalar quantity
• Speed is scalar quantity
• Displacement is vector quantity

Answer 2

$\sf{\underbrace\green{Answer \implies (a)\:Displacement}}$

$\sf\red{\underline{\underline{Reason:}}}$

$\sf{During \:some\: interval,\: distance\: cannot\: be\: zero\: so\: as}$$\sf{speed \:but \:displacement\: may\: be \:zero\: because \:final}$$\sf{position\: of \:the \:particle\: may\: coincide\: with\: its\: initial}$$\sf{position.}$

$\sf\purple{\underline{\underline{In\:Detail:}}}$

(1️⃣)$\sf{For \:Scalar\: quantities, \:they\: depends\: only \:on\: the}$$\sf{ magnitude \:of \:the\: term, \:direction\: doesn't\: matter \:of}$$\sf{scalar \:quantities.}$

(2️⃣).$\sf{For\: the \:vector\: quantity, \:it\: depends \:upon \:the}$$\sf{direction\: of \:that \:vector \:as \:well\: as\: magnitude.}$

$\sf{So, \:sum\: can \:be\: zero\: after\: some\: time.}$

$\sf\orange{\underline{ In\: this \:case\: only \:Displacement \:can \:be}}$$\sf\orange{\underline{ zero\: after\: some \:time.}}$