wht is the sum of the 1st 10 term of ap 41,36,31,26?
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Answered by
14
Answer:
Given AP is 41,36,31,26,21,..... Sum of this AP will be ,41+36+31+26+21..... +10terms.
Step-by-step explanation:
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Answered by
2
sn = N/2 ( 2a + ( N - 1 ) ( d ) )
= 10/2 ( 2x 41 + (10 - 1) -5
= 5 x 82-45
= 5x37
= 185
hence proved
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