Math, asked by devanandprasad5486, 11 months ago

Wht value of 'k' is k-3, 2k+1, 4k+3 is an ap?

Answers

Answered by shauryadawra13
0

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

FROM THE FORMULA  b^2=a*c

(2k+1)^2=(k-3)*(4k+3)

4k^2+1  =  4k^2  +  3k  -  12k  -  9.

0= -9k -10

9k = -10

k = -10\9

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