Why 1/4 and -1 are zeroes of the polynomial p( x ) = 4x² + 3x - 1 ?
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Answered by
33
Hey mate,
========
Given,
p ( x ) = 4x^ 2 + 3x -1
Now, in order to determine whether 1/4 is the zero of the given polynomial or not we need to substitute 1/4 in place of x..i.e.
p ( 1/4 ) = 4 × (1/4)^2 + 3 × 1/4 - 1
= 1/4 + 3/4 - 1
= 4/4 -1
= 1 - 1
= 0
Since , p ( 1/4 ) = 0
Therefore , 1/4 is the zero of the given polynomial p ( x ).
Similarly ....,
p ( -1 ) = 4 ( -1 )^2 + 3 (-1) - 1
= 4 - 3 - 1
= 1 - 1
= 0
Since, p ( -1 ) = 0
Therefore, we have -1 as the zero of the given polynomial p ( x )
Hope it helps...!!
#racks
========
Given,
p ( x ) = 4x^ 2 + 3x -1
Now, in order to determine whether 1/4 is the zero of the given polynomial or not we need to substitute 1/4 in place of x..i.e.
p ( 1/4 ) = 4 × (1/4)^2 + 3 × 1/4 - 1
= 1/4 + 3/4 - 1
= 4/4 -1
= 1 - 1
= 0
Since , p ( 1/4 ) = 0
Therefore , 1/4 is the zero of the given polynomial p ( x ).
Similarly ....,
p ( -1 ) = 4 ( -1 )^2 + 3 (-1) - 1
= 4 - 3 - 1
= 1 - 1
= 0
Since, p ( -1 ) = 0
Therefore, we have -1 as the zero of the given polynomial p ( x )
Hope it helps...!!
#racks
Answered by
4
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