why bond angle of water is greater than of2?
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X = F or H and the compound they are forming is either H2O or OF2. The degree repulsion in the molecule depends on the electronegativity of X. Hydrogen is the least electronegative. ... This increases the repulsion with the lone pairs in the outer shell of oxygen and thus increases the bond angle.
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Explanation:
O is more electronegative than H and so bond pairs in OH2 will be more towards O, whereas since F is more electronegative than O, so bond pairs in OF2 is more towards F and therefore OF2 face a lesser bp-bp repulsion than OH2. This justifies the higher bond angle of OH2 over OF2.
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