Why ccl4 is used in the hydroboration addition of alkene?
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The addition of CCl4 to alkenes in presence of peroxides is a free radical reaction. So what I have thought is, while the reaction is going on, there are the following species present: RCH=CH2 (reactant), RC^HCH2CCl3 (^ represents the electron on the free radical) and the product RCHClCH2CCl3.
When the free radical reacts with RCH=CH2 it gives the main product RCHClCH2CCl3 and ⋅CCl3. So probably the second product is formed by reaction of ⋅CH(R)CH2CCl3 with RCHClCH2CCl3?
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