Question

Why does a block of plastic released under water come up to the surface of the water.

long answer type question​

Answer 1

Answer:

block of mass m = 1 kg moving on a hortzontal surface with speed v, = 4 ms* enters a rough patch ranging from x = 0.10 m to r= 2.01 m. The retarding force E on the block in this range is inversely proportional to x over this range. F, for 0.1 < *< 2.01 m = 0 for x< 0.1 m and x> 2.01 m where, k = 04 ]. What is the final kinetic energy and speed v, of the block as it crosses this patch

Answer 2

Answer:

Density of plastic block is less than the density of water. Thus, when it floats, it is partially immersed in water such that its weight gets balanced with the buoyant force acting on it. When it is put completely in water, buoyant force on it becomes more than its weight. Thus, when it is released, it comes up to the surface of the water due to a net upward force acting on it.