Why does a freely falling body demonstrate accelerated Motion??
Answers
Answer:
When we say freely falling, and it is generally while studying NLM, we mean that the body moving under gravitational pull and there is no other force to oppose it.
And since a continuous force is applied then, according to newton's first law, the body of defined mass shall be accelerated and it would be proportional to F/M
Answer:
Acceleration due to gravity
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When a body is dropped from some highest then it falls vertically downward toward the earth gravitational force.
Suppose we dropped a body of mass *m* from a distance *R* from the centre of the earth and take the mass of the earth be *M*
Then the force exerted by the earth on that body is equal to
F = G × M×m/R²...(1)
(G is constant)
And this continous force of the earth on the falling body produces the acceleration on the body due to which it moves downward direction toward the earth centre.
We also know that
F = m × a
So acceleration to be calculated by the formula
a = F/m............. (2)
Now ,
putting the value of F from the equazion (1) in a= F/m
a = G×M/R²
This formula is used for the calculation the aceleration due to gravity on the earth surface .
Most Commonly the acceleration due to gravity produces on a freely calling body at the rate of
9.8m/s²
{ Note the acceleration due to gravity on each and every parts of earth surface is not same!
because acceleration is inversly proportional to 1/R²}
The acceleration due to gravity is maximum at the pole is that but minimum at the equator