Question

why electron can't exist in nucleus? Explain.​

Answer 1

Answer:

due to its energy..

...

Answer 2

Answer:

We can explain this by heisenberg's uncertainty principle .

We can explain this by heisenberg's uncertainty principle .Formula =

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4π

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4π

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·m

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)m= 9.1 x 10^-31kg, h= 6.626x 10^-34

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)m= 9.1 x 10^-31kg, h= 6.626x 10^-34If we substitute all the values and just observe the power on ten we get

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)m= 9.1 x 10^-31kg, h= 6.626x 10^-34If we substitute all the values and just observe the power on ten we get Δv > _______x10^11

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)m= 9.1 x 10^-31kg, h= 6.626x 10^-34If we substitute all the values and just observe the power on ten we get Δv > _______x10^11Which is not possible as an electron cannot have velocity greater than the velocity of light(3.0x10^8)

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)m= 9.1 x 10^-31kg, h= 6.626x 10^-34If we substitute all the values and just observe the power on ten we get Δv > _______x10^11Which is not possible as an electron cannot have velocity greater than the velocity of light(3.0x10^8)Hence an electron cannot exist in nucleus.

We can explain this by heisenberg's uncertainty principle .Formula = Δx . Δp > h/4πΔx . m . Δv> h/4πΔv> h/4π·Δx·mNow is electron is in the nucleus then Δx= 10^-15m (size of nucleus)m= 9.1 x 10^-31kg, h= 6.626x 10^-34If we substitute all the values and just observe the power on ten we get Δv > _______x10^11Which is not possible as an electron cannot have velocity greater than the velocity of light(3.0x10^8)Hence an electron cannot exist in nucleus.Read more on Brainly.in - https://brainly.in/question/1489416#readmore