Question

why in aquou solution of La (OH)3 ,Lu(OH)3 and Ce(OH)3 colorless​

Answer 1

Answer:

The ionic radii of Zr

4+

and Hf

4+

are almost similar due to the lanthanide contraction which means the steady decrease in the size of the atoms with the increase from lanthanum through Lutetium due to the poor shielding of the 4f e

−

, the e

−

pull towards the nucleus increases thereby decreasing the size.

Ce

4+

act as oxidizing agent as it oxidizes other elements by itself getting reduced as Ce

3+

is more stable than Ce

4+

oxidation state so in order to attain stable +3 oxidation it gets reduced.

The basic characteristics of lanthanoid hydroxides decrease down the group.

Thus La(OH)

3

is the most basic.

Thus only statement II and III are correct.

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