Why is binding energy oer nucleon constant for 20
Answers
The famous Einstein’s theory of special relativity established the fact that mass is another form of energy. Also, you can convert the mass-energy into other forms of energy. This opened the doors to a better understanding of nuclear masses and the interaction of nuclei with each other. In this article, we will look at the binding energy of a nucleus which is essential to understand the nuclear fission and fusion processes.
Structure of Atom
Atomic mass and composition of nucleus
Basics of Isotopes,Isotones and Isobars
According to Einstein’s mass-energy equivalence relation, we know that,
E = mc2 … (1)
where c is the velocity of light in vacuum and is ≅ 3 x 108 m/s. Also, E is the energy equivalent of the mass, ‘m’. Experimental studies of nuclear reactions between nucleons, nuclei, electrons and other more recently discovered particles. According to the Law of Conservation of Energy, we know that in a reaction, the initial and final energy is the same provided we take the mass-energy into consideration.
Nuclear Binding Energy
We know that the nucleus is made up of protons and neutrons. So, logically, the mass of the nucleus = the sum of masses of the protons and neutrons, right? Not really! The nuclear mass (M) is always less than this sum. To e=understand this better, let’s look at an example,
168O has 8 protons and 8 neutrons. Now,
Mass of 8 neutrons = 8 × 1.00866 u
Mass of 8 protons = 8 × 1.00727 u
Mass of 8 electrons = 8 × 0.00055 u
Therefore the expected mass of 168O nucleus = = 8 × 2.01593 u = 16.12744 u.
We know from mass spectroscopy experiments that the atomic mass of 168O is 15.99493u. Subtracting the mass of 8 electrons from this, we get the experimental mass of 168O nucleus = 15.99053u (15.99493u – [8 x 0.00055u]). Hence, we see that there is a difference between the two numbers of 0.13691u (16.12744 u – 15.99053u).
In simple words, the mass of the 168O nucleus is less than the total mass of its constituents by 0.13691u. This difference in mass of a nucleus and its constituents is called the mass defect (ΔM) and is given by
ΔM = [Zmp + (A – Z)mn] – M … (2)
Answer:
Explanation:
The binding energy is of very short order range force. So beyond a certain amount of range the force has no influence beyond that that's y after certain number the binding energy per nucleon do not change even if we add more nucleons.
Hope it helps you ❤️