Chemistry, asked by MdAnupMalik5452, 10 months ago

Why KCl is used in comductometer experiment to determine specific conductance?

Answers

Answered by Anonymous
13

Answer:

According to the basic law of electrochemistry:

Specific conductance (K, kappa) =C. l/a.

Where l/a is cell constant.

i.e., Specific conductance (K, kappa) is equal to the product of the conductance of the electrolyte and the cell constant.

Or cell constant= Specific conductance/ Conductance.

(Cell constant can be determined on dividing Specific conductance by Conductance)

NOW CONDUCTANCE CAN BE EXPRESSED EITHER AS MOLAR CONDUCTANCE OR EQUIVALENT CONDUCTANCE.

The molar conductance of the standard KCl solution is inversely proportional to its molarity while its equivalent conductance is inversely proportional to its normality for a given volume Vcm^3.So cell constant will also change with the change with molarity or normality of KCl solution.

Answered by ItsSpiderman44
0

Answer:

Specific conductance (K, kappa) =C. l/a

Where l/a is cell constant.

i.e., Specific conductance (K, kappa) is equal to the product of the conductance of the electrolyte and the cell constant.

Or cell constant= Specific conductance/ Conductance.

(Cell constant can be determined on dividing Specific conductance by Conductance)

NOW CONDUCTANCE CAN BE EXPRESSED EITHER AS MOLAR CONDUCTANCE OR EQUIVALENT CONDUCTANCE.

The molar conductance of the standard KCl solution is inversely proportional to its molarity while its equivalent conductance is inversely proportional to its normality for a given volume Vcm^3.So cell constant will also change with the change with molarity or normality of KCl solution.

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