Why lateral displacement depends on thickness of glass slab and angle of incidence ?
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If the glass slab were not present, the incident ray would travel a distance a in the horizontal direction. When the glass slab is present, the ray only travels a distance b due to refraction. The lateral displacement s is therefore
s=a−b
We find a and b using some simple geometry from the figure.
a=dtanθ1
b=dtanθ2
However, we can calculate θ2 from θ1 using Snell’s law.
n1sinθ1=n2sinθ2
θ2=sin−1(n1n2)
Plugging this expression for θ2 into the equation for b gives
b=dtan[sin−1(n1n2)]=dn1/n21−(n1/n2)2√
The lateral displacement s is
s=dtanθ1−dn1/n21−(n1/n2)2√=d[tanθ1−n1/n21−(n1/n2)2√]
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bimlesh99:
Thank you but i want it in 3 lines
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Lateral Displacement indeeddepends upon the thickness of the glass slab the light hasto pass through. ... This isbecause it travels a greater length through the medium compared to the ray of light
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