Why limit t tends to infinty f(t)e^-t is zero when f(t) tends to zero at infinity?
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The limit as t approaches infinity of e^-t = 0 because e^-t can be written as 1/e^t, and as you increase e^1 the number gets bigger and bigger, and if you divide 1 by a huge number the answer approaches zero.
Step-by-step explanation:
The graph of e^-t is attached, as you can see when you approach infinity the limit approaches zero.
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