Why NA+have more ionization enthalpy than NE
Answers
Answered by
36
The ionization enthalpy OF NA+ ion is more than twice that of NE.
The NA+ ion has higher effective nuclear charge (+9) than NE(+8).So,the electron in the outermost shell (2s2 2p6) are more tightly bound to the nucleus in NA+ ion that in neutral NE atom.Higher the effective nuclear charge .higher will be the ionization energy.
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The NA+ ion has higher effective nuclear charge (+9) than NE(+8).So,the electron in the outermost shell (2s2 2p6) are more tightly bound to the nucleus in NA+ ion that in neutral NE atom.Higher the effective nuclear charge .higher will be the ionization energy.
I HOPE THIS ANSWER WILL HELP U!!!!!!!!!!!!!!!!!
CHEERS!!!!!!!!!!!!!!!!!!!!!!!!!
Answered by
24
Answer:
As we know Na has electronic configuration 1s2,2s2,2p6,3s1. It has just one electron in its outer most or valence shell we can say. After losing one electron, its e- configuration becomes 1s2,2s2,2p6 which is similar to neon's configuration.
Explanation:
Now Na+ atom has 10 electrons and 11 protons due to which the protons present in nucleus of atom will apply more force on electrons as compared to neutral sodium. Now, to extract one more atom from shell of Na+ atom requires really much amount of energy which is greater than the energy required to ionise Ne atom. That's all the explanation! : )
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