Why p-π and d-π bonds in so3 sulphur is in excited state?
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Sulphur has Ec - 3s² 3p⁴ ...in so3 it is in 2nd excited state......3s¹ 3p³ 3d² because it needs 6 unpaired electron to form bonds now 3 of the bonds are clearly sigma bonds made by one s and 2 p orbitals so there will be 1 p pi and 2 d pi bonds
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