Why s-character is directly proportional to electronegativity?
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Hybrid orbitals having more s character are more electronegative because s orbital is nearer to the nucleus and hence more attracted by the nucleus. ... Hence attraction of electron in a bond towards the nucleus decreases in the order sp>sp2>sp3. Hence electronegativity decreases in above order.
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Explanation:
More is the s-character present in a hybrid orbital of an element, more will be the electronegativity of that element.
This is because s-orbitals have greater penetrativity and it experiences a greater effective nuclear change as they are closer to the nucleus of an atom.
Whereas p-orbitals being away from the nucleus of an atom are not able to shield out the effect of s-orbitals.
As a result, electronegativity increases due to increase in electron density in an s-orbital.
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