Math, asked by IshikaSarkar, 10 months ago

Why
$p {}^{4} - 256 = (p - 4)(p + 4)(p {}^{2} - 16)$

Answers

Answered by Anonymous

Answer :D

p⁴ - 256 = (p - 4) (p + 4) (p² - 16)

p⁴ - 256 = (p² - 16) (p² - 16)

p⁴ - 256 = (p² - 16)²

p⁴ - 256 = p⁴ - 256

LHS = RHS

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Answered by Anonymous

p⁴ - 256 = (p - 4) (p + 4) (p² - 16)

p⁴ - 256 = (p² - 16) (p² - 16)

p⁴ - 256 = (p² - 16)²

p⁴ - 256 = p⁴ - 256

LHS = RHS

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Answers

Answer :D

p⁴ - 256 = (p - 4) (p + 4) (p² - 16)

p⁴ - 256 = (p² - 16) (p² - 16)

p⁴ - 256 = (p² - 16)²

p⁴ - 256 = p⁴ - 256

LHS = RHS

Why
$p {}^{4} - 256 = (p - 4)(p + 4)(p {}^{2} - 16)$