why the base of a transistor connected to a low potential ??
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For an NPN transistor the base is of low (positive)potential to ground, because only a small positive base current is required to control the larger current from collector to emitter.
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The base of a bipolar junction transistor, when biased so that conventional current flows from the base to the emitter, will be one junction voltage above the emitter. Therefore, if a circuit has the emitter at zero potential (circuit ground), the base will be at 0V + Vbe, which will typically be 0.65V (for a small-signal silicon NPN transistor where the bias current is within its recommended operating range).
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