Question

why value of g 0 at centre of earth you explain me by navneet​

Answer 1

Explanation:

g - acceleration due to graviational force mean force experienced per unit mass(1kg)

g = $\frac{F_g}{m}$

at the centre of the earth, all mass of the earth tries to pull equally in all directions hence net gravitational force is zero.

∵ g =  $\frac{F_g}{m}$ = 0/m = 0m/s²

Answer 2

Explanation:

By the formula :

g = GMe/R^2.

Note: When R =0 then The value of g is zero.

Hence the value of g at centre of earth is zero.

And this value increase as we move toward the surface of earth.

Thank you.