Question

why wave numberis inversely proportional to the wave length ​

Answer 1

Answer:

e IR-spectrum is "Intensity" versus "Energy" (E), given as wavenumber (ni*) in [cm-1] (NB! Not in [m-1])

The relationship wavenumber (ni*) versus wavelength (lambda) is:

ni* = 1/lambda

But the freqiency (ni) and lambda are joined in relationship:

ni = c/lambda (c = 299792458 m.s-1)

And this is, because of: E = h.(ni).

So that if you would like to know to each ni* in [cm-1], corresponding frequency ni or lambda, you should transform the units:

For example, for mid-IR region should be:

5000 - 400 cm-1 region (ni*) or

2000 - 25000 nm (lambda, wavelength) or

6.67 - 83.4 fs (or 10-15 s) (ni).

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Answer 2

Answer:

this is because if wave nimberis are more then the wave length will be less.....and vice versa