Question

will be marked brainliest if right

Answer 1

Solution:

$\frac{ {( {x}^{3} . {x}^{2}) }^{2} }{ ({x}^{3} )^{3}.x } \\ \\ \frac{ { {(x}^{(3 + 2)} )}^{2} }{ {x}^{3.3}.x } \\ \\ \frac{ {x}^{(5.2)} }{ {x}^{9} .x} \\ \\ \frac{ {x}^{10} }{ {x}^{9+ 1} } \\ \\ \frac{ {x}^{10} }{ {x}^{10} } \\ \\ {x}^{(10 - 10)} \\ \\ {x}^{0} = 1$

Using laws of Indices

${a}^{2} . {a}^{3} = {a}^{(2 + 3)}$

$\frac{ {a}^{3} }{ {a}^{2} } \\ \\ {a}^{(3 - 2)}$

${ ({a}^{2}) }^{3} = {a}^{(2.3)}$