Question

WILL GIVE 40 POINTS
y=-|x-2|+2
find all values of x such that:
1. y>0
2. y<0
3. y=0

Answer 1

Answer:

Step-by-step explanation:

y = -(x-2)+2 = - x + 4

y = x - 2 + 2 = x

when, y = 0, x = 0, 4

when, y > 0, x < 4, x > 0

when, y < 0, x > 4, x < 0

Answer 2

Answer:

2) y<0 because |x-2|+2

y= x-2+2

now 2 2 cancel

the value of x 0

x=0

y= x<0 Ans