Question

Will give brainliest for shown work

Let ​ f(x)=x2+17x+72 ​ .



What are the zeros of the function?

​Enter your answers in the boxes. ​

Answer 1

Heya !!!


F(X) = X²+17X+72


This equation is in the form of AX²+BX+C = 0



Where,

A = 1 , B = 17 and C = 72


Discriminant (D) = B²-4AC

=> (17)² - 4 × 1 × 72


=> 289 - 4 × 72


=> 289 - 288


=> 1



X = - B + ✓D / 2A OR - B - ✓D/ 2A


X = -17 + ✓1/ 2 × 1 OR -17 - ✓1/2 × 1


X = -17 +1/2 OR -17 - 1/2


X = -16/2 OR -18/2


X = -8 OR -9



Hence,


-8 and -9 are the two zeroes of the given polynomial.

HOPE IT WILL HELP YOU...... ;-)

Answer 2

x^2+17x+72=0
x^2+ 9x + 8x + 72=0
x(x+9)+ 8(x+9)=0
(x+9)(x+8)=0
roots: -8.-9