Question

WILL MARK AS BRAINLIEST IF ANSWERED CORRECTLY IN SIMPLEST FORM

Answer 1

Question :

Eight students are competing for a blue, red. and yellow ribbon for their agriculture project.

How many different ways are there to present those ribbons if the order matters?  

Answer:

336

b). option is correct.

Step-by-step explanation:

Given :

Eight students are competing for a blue, red. and yellow ribbon for their agriculture project.

Numbers of ways are there to present those ribbons are as :

$\sf \longrightarrow \ ^8P_3$

We know :

$\sf \longrightarrow \ ^nP_r = \dfrac{n!}{(n-r)!}$

= > 8 ! / 5 !

= > 8 × 7 × 6 × 5 ! / 5 !

= > 8 × 7 × 6

= > 336 ways .

Therefore , we get required answer.

Answer 2

$\huge\bold\green{Question}$

Eight students are competing for a blue, red. and yellow ribbon for their agriculture project. How many different ways are there to present those ribbons if the order matters?

$\huge\bold\green{Question}$

According to the question we have given that :-

Eight students are competing for a red, yellow and blue ribbon for their agriculture project.

So ,Numbers of ways to present those ribbons are :-

In this we use permutation relation .So,

$\sf \implies ^{8} p _{3}$

So , ams we know that the formula of permutation is

$\begin{lgathered}\orange\implies\tt \ ^nP_r = \dfrac{n!}{(n-r)!} \\\\\end{lgathered}$

Now , by solving this

= 8 ! / 5 !

= 8 × 7 × 6 × 5 ! / 5 !

= 8 × 7 × 6

= 336

Hence , the required value of ways is 336

So , Option ( b ) is the correct option