will the surface area of a cylinder change if you double the height or double the radius explain your reasoning
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let initial radius be r and height be h
Surface area of cylinder initially
SA = 2pi r h + 2 pi r^2 = 2pi (rh + r^2)
When radius is doubled
r' = 2r
Thus
Surface area becomes
SA' = 2 pi r' h + 2 pi r'^2
SA' = 2 pi 2r h + 2 pi 4 r^2
= 2 pi (2 rh + 4r^2)
= 2 * 2 pi (rh+ 2r^2)
= 2 * [2 pirh + 2pir^2 + 2 pir^2]
= 2 * [ 2pi(rh+r^2) + 2 pi r^2]
SA' = 2*[SA + 2 pi r^2]
Surface area of cylinder initially
SA = 2pi r h + 2 pi r^2 = 2pi (rh + r^2)
When radius is doubled
r' = 2r
Thus
Surface area becomes
SA' = 2 pi r' h + 2 pi r'^2
SA' = 2 pi 2r h + 2 pi 4 r^2
= 2 pi (2 rh + 4r^2)
= 2 * 2 pi (rh+ 2r^2)
= 2 * [2 pirh + 2pir^2 + 2 pir^2]
= 2 * [ 2pi(rh+r^2) + 2 pi r^2]
SA' = 2*[SA + 2 pi r^2]
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