Question

Wind is blowing from the south at 5 m s⁻¹. To a cyclist it appears to be blowing from the east at 5 m s⁻¹. Show that the velocity of a cyclist is 1 m s⁻¹ towards north east.

Answer 1

wind is blowing from south at 5m/s .

e.g., velocity of wind , $v_w$= -5j m/s

a/c to question,
To a cyclist it appears to be blowing from the east at 5m/s .

e.g., velocity of wind with respect to cyclist , $v_{wc}=v_w-v_c$

$5\hat{i}=-5\hat{j}-v_c$

$v_c=5\hat{i}+5\hat{j}$

hence, velocity of cyclist is √(5² + 5²) = 5√2 m/s in North - east direction

[ as i and j both are positive so, it is in 1st quadrant ]

Answer 2

Answer:

hope this will help you

Explanation:

wind is blowing from south at 5m/s .

e.g., velocity of wind , = -5j m/s

a/c to question,

To a cyclist it appears to be blowing from the east at 5m/s .

e.g., velocity of wind with respect to cyclist ,  

hence, velocity of cyclist is √(5² + 5²) = 5√2 m/s in North - east direction

[ as i and j both are positive so, it is in 1st quadrant ]