Math, asked by bhatia83nisha, 11 months ago

wire bent in the shape of a rectangle with
12 cm and 10 cm is straightened out and
bent in the shape of a circle. Find the radius
and area of the circle.

Answers

Answered by student5649
8

Step-by-step explanation:

Length of the rectangle = 18 cm

Breadth of the rectangle = 15 cm

. : . Perimeter of the rectangle = 2 ( 18 + 15 ) cm

= 2 x 33 cm

= 66 cm

. : . Circumference of the circle = 66 cm

Let the radius of the circle be r сm

2πr=66

2 \times  \frac{22}{4}  \times r = 66

 \frac{66 \times 7}{22 \times 2} = r

r=10.5

area of circle =πr²

 \frac{22}{7}  \times (10.5) {}^{2}

=346.5

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Answered by manish200334
16

Answer:

7cm

Step-by-step explanation:

The perimeter of rectangle=2[L+B]

=2×[12+10]

=2×22cm

=44cm

The circumference of circle=2πr

44cm=2×22/7×r

44×7/44=r

7cm=r

The area of circle =πr^2

=22/7×7×7

=154cm^2

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