wire is bent in the shape ofa rectangle Its length is 40 cm and breadth is 24cm. It the same wire
mrhent in the shape ora square what will be the measure of each side? Also find which shape
enclosed more area
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Answer:
Measure of each side of square is 32 cm and Square shape has more area
Step-by-step explanation:
Perimeter of the rectangle wire is
= 2( length + breadth)
=2(40+24)=128 cm
let "a" be the sides of the square
Perimeter of rectangle is equal to perimeter of the square
128 = 4a
a= 128/4
a= 32 cm
Measure of each side of square is 32 cm
Area of rectangle = l x b = 40 x 24 = 960 sq cm
Area of the square = a x a = 32 x 32 = 1024
Square shape has more area
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Length = 40cm
Breadth=24cm
Perimeter of rectangle =2(l+b)
=2(24+40)
=2(64)
=128cm
s=side of a square
Perimeter of square = 4s
128=4s
s=32cm
Therefore each side of square so formed is 32cm
Area of rectangle = lb
=40(24)
=960cm square
Area of square= s multiplied by s
=32(32)
=1024cm square
Therefore square encloses more area than rectangle
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Breadth=24cm
Perimeter of rectangle =2(l+b)
=2(24+40)
=2(64)
=128cm
s=side of a square
Perimeter of square = 4s
128=4s
s=32cm
Therefore each side of square so formed is 32cm
Area of rectangle = lb
=40(24)
=960cm square
Area of square= s multiplied by s
=32(32)
=1024cm square
Therefore square encloses more area than rectangle
PLS MARK IT AS BRAINLIEST
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