with centre o quadrants of 2 circles are drawn if is = 5 CM an = 7cm find the area of the shaded region (take π=22/7)
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Area of designed region= Area of first quadrant+Area of second quadrant−Area of square.
=
360
θ
×πr
2
+
360
θ
×πr
2
−side×side
=2
360
θ
×πr
2
−side×side
=2×
360
90
×
7
22
×8×8−8×8
=
7
2×352
−64=
7
704−448
=
7
256
cm
2
Step-by-step explanation:
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