Math, asked by rajveer54, 1 year ago

with full solution please

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Answered by Anonymous
0

1156 \div 4 = 289
289 students are required to form one side of the square.

QGP: Hi! You missed the fact that corner students are counted twice in 4l. Please edit your answer to account for that fact.
Answered by QGP
1
Hey There!!


This question has two interpretations. We will consider both:


1) The students form each row and column. That is, the entire area of square is filled with students.

Here, 1156 students are forming the square.

The students form many rows and columns. 


Let length of square be l students. 

Then there are l students in every row and column. 

So, Total Number of students in the square = l^2


We have:

1156 = l^2 \\ \\ \implies l = \sqrt{1156} \\ \\ \implies \boxed{l=34}

Thus, there are 34 students form a side.



2) The students form only the boundary of the square.

In this case, the students don't fill the area. They only form the perimeter. 


Let length of square be l students. 

Then the total perimeter is 4l

However, in counting 4l, we have counted each corner student twice. 

So, actual number of students forming the perimeter is 4l-4

We have:

1156 = 4l-4 \\ \\ \implies 1160 = 4l \\ \\ \implies \boxed{l=290}


Thus, there are 290 students on each side of square.


Hope it helps
Purva
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