With out finding the cubes,factories the following:
(X-y)³+(y-x)³+(z-x)³.
Answers
Answered by
3
Hope it helps ✌️✌️
Please mark as Brainliest
Please mark as Brainliest
Attachments:
parveshyadavbhai:
Thnk u
Answered by
1
Hello user☺☺☺
Since , a+b+c =0
So, a^3 + b^3 + c^3 = 3abc
So, factorization will be...
3(x-y)(y-z)(z-x)
Hope it works
Since , a+b+c =0
So, a^3 + b^3 + c^3 = 3abc
So, factorization will be...
3(x-y)(y-z)(z-x)
Hope it works
Similar questions