Question

with respect to the roots of x^2-2x-3=0, we can say that
a)both of them are natural numbers
b)both of them are integers.
c)one of the root is zero
d) roots are real

Answer 1

Step-by-step explanation:

x²-2x-3=0

x²-2x-x-3=0

x(x-2)-1(x-2)=0

(x-1)(x-2)=0

x-1=0 & x-2=0

x=1 & 2

a) yes; both 1 & 2 are natural no.

b) no, no any root is zero

c) yes; both 1 & 2 are real natural numbers.

I hope it will help you.

Answer 2

D=(-2)^2-4(1)(-3)

=5+12=17

√D= irrational

so option (d) roots are real