Question

With the help of a circuit diagram prove that when a number of resistors are connected in parallel, the reciprocal of equivalent resistance of the combination is equal to the sum of the reciprocals of the individual resistances of the resistors.
Pind the resistance between A and B in the given network
b
zn

A a 411 C B


CBSE Class X Science LA (5 Marks)

Answer 1

Answer:

1/Req  = 1/R₁  +1/R₂  + 1/R₃ +.........................+ 1/Rₙ

Explanation:

Let say there are n Resistors Connected in Parallell

R₁ , R₂ , R₃ ,...........................Rₙ

And Volatge applied = V

as resistance are in parallel so voltage across Each Resistance = V

Curren through each resistore respectively

I₁ , I₂ , I₃ ................................ Iₙ

Total Current I = I₁ + I₂ + I₃ +................................+ Iₙ

=> V/Req  = V/R₁  +V/R₂  + V/R₃ +.........................+ V/Rₙ

dividing by V both sides

=> 1/Req  = 1/R₁  +1/R₂  + 1/R₃ +.........................+ 1/Rₙ

hence the reciprocal of equivalent resistance of the combination is equal to the sum of the reciprocals of the individual resistances of the resistors.

Answer 2

Hope it's help you...........