Question

With the help of an example, explain, how
the neutron to proton ratio changes
during a-decay of a nucleus.​

Answer 1

Answer:

Alpha decay involves the ejection of a helium nucleus, which is just two protons and two neutrons. This means that the atomic mass decreases by 4 and the atomic number decreases by two. This decay is typical of radioisotopes which have nuclei that are too large.

Explanation:

Force between nucleons is called nuclear forces. It is one of the four fundamental forces in nature.

Properties :

(i) It is an attractive force.

(ii) It is independent of the interacting nucleons.

(iii) It is a short range force. (iv) Itisanon-centralforce.

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Answer 2

During alpha decay, the parent nuclei splits into daughter nuclei and alpha particles. A large amount of energy is released during this decay.

Explanation:

During alpha decay, the parent nuclei splits into daughter nuclei and alpha particles. A large amount of energy is released during this decay.

A helium atom consists of two protons a and two neutrons.

The atomic mass of the parent atom decrease by 4 and atomic number decreases by 2.

The example is given as:

Ra 226 - 88 ------> Rn 222 - 86 + He 4 - 2 + 4.78 MeV