Question

With vertices A,B and C of a triangle ABC as centres, arcs are drawn with 5cm each. With sides AB=14cm, BC=48cm and CA =50cm, find Area of whole triangle minus the sum of the three sectors

Answer 1

According to question

Area of triangle can be calculated by

S = AB + BC + AC/2
    = 14 + 48 + 50 / 2
    = 56

Thus
Area  = S root [(S-AB) + (S-BC) + (S-AC)]
          = S root [ (56 - 14) + (56 - 48 + (56 - 50)]
          = 56 root [ 42 + 8 + 6]
          = 56 root [56]
          = 419.06 Cm^2