Question

with what speed must a ball be throwm vertically up in order to rise to a maximum height of 53.7 m​

Answer 1

Answer:

Explanation:

Hey. Hence, if the ball is thrown at a speed of 32.44 m/s vertically upwards it will gain a vertical height of 53.7 m.

Answer 2

GiveN :-

• A ball is throwm up at speed is 4 m/s.

To FinD :-

• The maximum highest reached by the ball.

SolutioN :-

Given that a ball reaches a maximum height of 53.7 m when thrown with some Velocity .We need to find the velocity. Let the speed be u .

$\sf:\implies \pink{ Height_{(maximum)}=\dfrac{u^2}{2g} }\\\\\sf:\implies 53.7 m= \dfrac{u^2}{2(10m/s^2)}\\\\\sf:\implies 53.7 =\dfrac{u^2}{20m/s^2}\\\\\sf:\implies u^2 = 53.7 m \times 20m/s^2 \\\\\sf:\implies u^2= 1074 m^2/s^2 \\\\\sf:\implies u =\sqrt{1074 m^2/s^2} \\\\\sf:\implies\underset{\blue{\tt Required\ Velocity}}{\underbrace{\boxed{\pink{\frak{ Velocity_{(projection)}= 32.77 m/s \approx 38 m/s }}}}}$