Question

With what speed should a body be thrown upwards so that the distances traversed in 5th and 6th second are equal ?

Answer 1

Here we will use the following equation of motion

S = ut - 0.5gt²

Take g = 10m/s²

S at the 5th seconds is :

S = 5u — 0.5 × 10 × 25

S = 5u — 125

S at the 6th second is :

S = 6u — 0.5 × 10 × 36

S = 6u — 180

Since these displacements are equal :

6u - 180 = 5u - 125

U = 180 - 125 = 55m / s

Answer 2

Answer:

Explanation:

Here we will use the following equation of motion

S = ut - 0.5gt²

Take g = 10m/s²

S at the 5th seconds is :

S = 5u — 0.5 × 10 × 25

S = 5u — 125

S at the 6th second is :

S = 6u — 0.5 × 10 × 36

S = 6u — 180

Since these displacements are equal :

6u - 180 = 5u - 125

U = 180 - 125 = 55m / s