Question

with what velocity a ball be projected vertically so that the distance covered by it in 5sec is twice the distance it covers in its 6 sec.take g as 10m/s^2.........

Answer 1

s=ut-1/2gt^2
u(5)-1/2(10)(5)^2 = u(6)-1/2(10)(6)^2/2
5u-125 = 6u-90
-35= u