With what velocity should a student of mass 60 kg run so that his kinetic energy becomes 270 J?
(A) 10 m/s
(B) 3 m/s
(C) 20 m/s
(D) 2.5 m/s
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☆☆ AS-SALAMU-ALYKUM☆☆
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♢ kinetic energy =1/2 mv^2
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♢ v^2=2×KINETIC energy ÷m
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♢ v=square root 2× kinetic energy÷m
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♢ v= square root 2×270÷60
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♢ v=square root 9
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♢ v=3m/s
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SO THE REQUIRED VELOCITY IS 3m/s
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♡♤♡ INSHALLAH IT WILL HELP U ♡♤♡
●●●●●●●●●●●●●●●●●●●
♢ kinetic energy =1/2 mv^2
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
♢ v^2=2×KINETIC energy ÷m
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
♢ v=square root 2× kinetic energy÷m
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
♢ v= square root 2×270÷60
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
♢ v=square root 9
▪▪▪▪▪▪▪▪▪▪▪▪▪▪
♢ v=3m/s
▪▪▪▪▪▪▪▪
SO THE REQUIRED VELOCITY IS 3m/s
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
●●●●●●●●●●●●●●●●●●●
♡♤♡ INSHALLAH IT WILL HELP U ♡♤♡
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